3/5 - 7/2x = 3/10
multiply all by 10
6 - 35/x =3
multiply all by x
6x -35 = 3x
subtract 3x from both sides
3x-35 = 0
add 35 to both sides
3x = 35
divide both sides by 3
x = 35/3
2007-06-20 02:59:01
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answer #1
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answered by jeremy s 2
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Read this question again carefully
3 / 5 - 7 / (2x) = 3 / 10
'x' is in denominator not in numerator
Steps : -
- 7 / (2x) = 3 / 10 - 3 / 5,
- 7 / (2x) = - 3 / 10,
Now,
x = 70 / 6 = 35 / 3.
2007-06-20 10:03:06
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answer #2
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answered by Vedic Astrologer 3
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3/5 - 7/2x = 3/10
I'm not sure where the 'x' lies in this expression. I came up with 2 probables.
PROBABLE 1
is it: 3/5 - 7/(2x) = 3/10
multiply both sides by 10x,
6x - 35 = 3x
6x - 3x = 35
3x = 35
x = 35/3
or
PROBABLE 2
is it: 3/5 - (7/2)x = 3/10
multiply both sides by 10,
6 - 35x = 3
35x = 6 - 3 = 3
x = 3/35
okay, it seems that the position of your 'x' is like in PROBABLE 2, whereas the answer is based on 'x' like in PROBABLE 1.
2007-06-20 10:20:30
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answer #3
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answered by jurassicko 4
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If the question is...
3/5 - (7/2)x = 3/10
First, subtract the (3/5)
-(7/2)x = 3/10 - 3/5
-(7/2)x = 3/10 - 6/10
-(7/2)x = -3/10
Now multiply by (-2/7)
x = (-3/10)(-2/7) = 6/70 = 3/35
**********************************
If the question is
3/5 - 7/(2x) = 3/10
First subtract the (3/5)
-7/(2x) = 3/10 - 3/5
-7/(2x) = -3/10
Cross multiply...
-7(10) = -3(2x)
-70 = -6x
-70 / -6 = x
70 / 6 = x
35 / 3 = x
2007-06-20 10:01:00
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answer #4
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answered by Mathematica 7
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Brackets must be used to clarify questions such as this.
If questiion is:
3/5 - (7/2).x = 3 / 10-----(X by 10)
6 - 35 x = 3
35x = 3
x = 3 / 35
However if question is:-
3/5 - 7 / (2x) = 3 / 10------(X by 10x)
6x - 35 = 3x
3x = 35
x = 35 / 3
Take your pick!
2007-06-20 10:56:26
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answer #5
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answered by Como 7
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3/5 - 7/2x = 3/10
or, -7/2x = 3/10 - 3/5
or, -7/2x = (3 - 6)/10
or, -7/2x = -3/10
minus sign on both sides cancel out
or 70 = 6x
or x= 70 /6=35/3
2007-06-20 10:01:14
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answer #6
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answered by The 1 Who Thinks HE Knows!!!!! 2
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multiply all terms by 10x to get rid of the demoninators and you get
6x - 35 = 3x
3x = 35
x= 35/3
2007-06-20 09:57:56
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answer #7
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answered by bz2hcy 3
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is it the question given or is it a problem sum???
2007-06-20 09:57:29
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answer #8
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answered by Neda 3
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