Yes it is.
Just plug it in to check:
5 - 9x = 68
5 - 9(-7) = 68
5 - (-63) = 68
5 + 63 = 68
68 = 68 <== the answer checks out
2007-06-20 02:33:39
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answer #1
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answered by C-Wryte 3
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It a rule that in an algebraic equation both sides are equal to each other, thus, find the the value of variable x, the balancing number so that the sides must be equal to each other.
5 -9x = 68
-9x = 68 - 5
-9x = 63
x = 63 / (-9)
x = - 7
Then prove if x really balances the two sides. We go back to the original equation substituting x with -7.
5 - (9 * [-7]) = 68
5 - (-63) = 68 Note: (-[-63]) becomes + 63)
5 + 63 = 68
68 = 68
2007-06-20 02:50:56
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answer #2
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answered by Jun Agruda 7
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Well, you can figure it out two ways...
1) Plug (-7) in for x and see if the equation is true...
5 - 9(-7) =? 68
5 + 63 =? 68
68 =? 68
TRUE, so yes, it is the solution.
2) Solve the equation for x.
5 - 9x = 68
5 - 9x - 5 = 68 - 5
-9x = 63
-9x / -9 = 63 / -9
x = -7
2007-06-20 02:34:18
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answer #3
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answered by Mathematica 7
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I assume you mean x = - 7
Yes x = - 7 is a solution for the equation
5 - 9x = 68
5 - 9x - 5 = 68 - 5
- 9x = 63
- 9x / - 9 = 63 / - 9
x = - 63/9
x = - 7
- - - - - - - --
Check
5 - 9x = 68
5 - 9(- 7) = 68
5 - (- 63) = 68
5 + 63 = 68
68 = 68
- - - - - - - - -s-
2007-06-20 02:45:08
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answer #4
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answered by SAMUEL D 7
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5-9x=68
-5 -5
-9x=63
x=-7
In fact, -7 is the only solution to that equation.
2007-06-20 02:36:58
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answer #5
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answered by ashley 3
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Yes, because minus 9 times minus 7 is plus 63.
So 5 + 63 = 68, which is correct.
2007-06-20 02:34:06
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answer #6
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answered by tsr21 6
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5-9x = 68
9x = -63
x = -7
YES.
2007-06-20 02:34:39
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answer #7
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answered by Enginurse 2
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5 - 9x = 68
or, -9x = 68 - 5
or, -9x = 63
or, x = 63/-9 = -7 thats ur answer which means u were correct!
2007-06-20 02:49:46
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answer #8
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answered by The 1 Who Thinks HE Knows!!!!! 2
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5-9x=68
-9x=68-5
-9x=63
x=63/-9=-7
yes, -7 is your solution.
2007-06-20 02:34:38
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answer #9
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answered by Anonymous
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yup it goes like;
5-9x=68
-9x=68-5
-9x=63
x=63/-9
x=-7
tht was easy
wht grade r u in?
2007-06-20 02:38:17
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answer #10
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answered by Anonymous
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