slope of the line through the points
slope = (y2-y1)/(x2-x1)
= (10-12)/(7-5)
= -2/2
= -1
any line perpendicular to that has the negative inverse slope
so
slope = 1
2007-06-20 02:32:00
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answer #1
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answered by jeremy s 2
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Perpendicular lines have slopes that are negative reciprocals of each other. Examples are m = 3, -1/3,
m = 3/4, -4/3, or, in your case,
(12 - 10)/(5 - 7) = 2/-2 = -1 = m,
so any line with a slope of 1 will be perpendicular to it.
2007-06-20 02:34:32
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answer #2
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answered by Gary H 6
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The slope of the line through those points is
(10-12) / (7-5) = -2/2 = -1
The perpendicular slope is -1 * (1/-1) = 1
Going a little further, you can find the equation of a line perpendicular to the line that passes through those points:
so using (y-y1) = m(x-x1)
we have
y-12 = 1 (x-5)
Simplifying to get to y=mx+b form:
y-12= x-5
y = x+7
2007-06-20 02:31:11
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answer #3
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answered by whitesox09 7
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the slope of the line through given points is (10-12)/(7-5)=-1
The slope of the perpendicular line is the negative reciprocal of this or +1. you could calculate it as -(difference in x)/(difference in y):
-(7-5)/(10-12) =-2/-2 = 1
2007-06-20 02:34:29
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answer #4
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answered by bignose68 4
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m = (10 - 12) / (7 - 5)
m = - 1
Slope of perpendicular line is 1
2007-06-20 03:45:37
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answer #5
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answered by Como 7
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the slope of the second line m2=(10-12)/(7-5)=-1
and since the first line is perpendicular to the second line then its slope m1 is 1
(m1*m2=-1)
2007-06-20 02:32:29
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answer #6
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answered by Anonymous
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Find the slope of the line passing through the points.
y2-y1/x2-x1
If your line is perpendicular, its slope is the opposite reciprocal. You must FLOP the original slope (FLip, OPposite)
2007-06-20 02:31:23
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answer #7
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answered by ania 2
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slope formula
m = y₂- y₁/ x₂- x₁
Ordered Pair
(5, 12)(7, 10)
m = 10 - 12 / 7 - 5
m = - 2 / 2
m = - 1
- - - - - - -
Slope is - 1
- - - - - - - - - -s-
2007-06-20 02:59:48
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answer #8
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answered by SAMUEL D 7
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