The Bugatti Veyron can do 252mph, so assuming you left a 45 degree ramp at that speed, could you cover a distance of 1600 m? (Let's say the ramp is 10m high)
If not, what distance would you cover, and how fast would you have to go to cover the distance?
2007-06-20 02:05:51 · 6 answers · asked by swordman 2 in Science & Mathematics ➔ Physics
sorry, the car weighs 1888kg
2007-06-20 02:17:31 · update #1
Just from an estimated calculation, I think the maximum range would be around 1250 metres and that is neglecting air resistance and the car slowing down during flight.
So I would say no, it couldn't jump a mile.
I would estimate you would probably need to be travelling around 160 metres per second (~358 mph) to jump a mile.
2007-06-20 02:25:57 · answer #1 · answered by Doctor Q 6 · 1⤊ 0⤋
Let's forget air resistance and negative lift and confine the problem to ballistics. Also, since we don't know what acceleration the car can manage up the ramp, let's assume its height is 0.
Then we have
V=252*5280*.3048/3600 = 112.65 m/s
Vx = V*cos(45deg) = 79.66 m/s
Vy = V*sin(45deg) = 79.66 m/s
t = 2*Vy/g = 8.12 s (g assumed = 9.81)
X = Vx*t = 646.8 m
From the above we can derive a general equation for distance given initial velocity V and launch angle theta (with no net change in height):
X = 2*V*sin(theta)*V*cos(theta)/g
From the double-angle formula (a trigonometric identity; see ref), 2*sin(theta)*cos(theta) = sin(2*theta), so
X = V^2*sin(2*theta)/g
The fact that X is propportional to sin(2*theta) shows that 45 deg is the launch angle that yields the maximum range.
2007-06-20 13:03:34 · answer #2 · answered by kirchwey 7 · 0⤊ 0⤋
You wouldn't go very far cos the Veyron develops a shed load of down force to keep it on the road - kind of like an upside down wing.
If you put a twist on your ramp so you jump upside down you will go much further before you die!!!
2007-06-20 09:16:34 · answer #3 · answered by Anonymous · 1⤊ 0⤋
Even ignoring air resistance you could only cover 1234m (only??!!)
Go to this site, scroll down and find the "Solve for range" section. 252mph is approx 110m/s so use this as the speed, and 45 degrees as the angle. It'll calculate range for you.
http://www.ajdesigner.com/phpprojectilemotion/range_equation.php
2007-06-20 10:31:48 · answer #4 · answered by Mike T 6 · 1⤊ 0⤋
You left a major factor out, the mass of the car. So if you can't figure out the y time you can't figure out the x distance.
2007-06-20 09:13:27 · answer #5 · answered by Khelben 6 · 1⤊ 0⤋
tehe! errr no!
2007-06-20 09:33:25 · answer #6 · answered by cauchi 1 · 0⤊ 0⤋