3/4 -5(4x -3) = 110
2007-06-20 00:57:00 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
its suppose to be 3/4x*
2007-06-20 00:58:21 · update #1
3/4 - 5(4x - 3) = 110
3/4 - (20x - 15) = 110
3/4 - 20x + 15 = 110
4(3/4) - 4(20x) + 4(15) = 4(110)
3 - 80x + 60 = 440
80x + 63 = 440
80x + 63 - 63 = 440 - 63
80x = 377
80x / 80 = 377 / 80
x = 377 / 80
x = 4 57/80
- - - - - - s-
2007-06-20 01:54:17 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
3/4 x - 5(4x -3) = 110
First get rid of brackets....
3/4 x - 20x + 15 = 110
-19 3/4 x + 15 = 110
- 19 3/4 x = 95
x = 95 / (-19 3/4) = -4 64/79 = -4.8101265823
2007-06-20 01:02:24 · answer #2 · answered by Doctor Q 6 · 0⤊ 0⤋
3/4 -5(4x -3) = 110
3/4 - 20x + 15 = 110
20x = 3/4+15-110
20x= (3+60-440)/4
x = -377/(4*20)
x= -377/80
2007-06-20 01:01:19 · answer #3 · answered by Anonymous · 0⤊ 0⤋
3/4 -5(4x-3)=110
on multiplying of 5 in bracket
3/4 -20x -5(-3)=110
3/4-20x+15=110
3/4+15-110=20x
3/4 - 95=20x
3-380/4=20x
-377=80x
x=-377/80
2007-06-20 01:05:10 · answer #4 · answered by Kirat K 2 · 1⤊ 0⤋
3/4 -5(4x -3) = 110
.75 - 20x + 12 = 110
12.75 - 20x = 110
-20x = 97.25
x = -4.8625
2007-06-20 01:00:57 · answer #5 · answered by fcas80 7 · 0⤊ 0⤋
3 - 20.(4x - 3) = 440
3 - 80x + 60 = 440
63 - 80x = 440
80x = - 377
x = - 377 / 80 (nasty looking answer!)
Going to have another go:-
(3/4).x - 5.(4x - 3) = 110
3x - 20.(4x - 3) = 440
3x - 80x + 60 = 440
- 77x = 380
x = - 380 / 77 (doesn`t look much better ! )
Never say die:-
(3/4)x² - 5(4x - 3) = 110
3x² - 20.(4x - 3) = 440
3x² - 80x + 60 = 440
3x² - 80x - 380 = 0
x = [80 ± √(80² + 4560)] / 6
x = [80 ± 104.7] / 6
x = 118 , x = - 12.4 (doesn`t look too good either!)
Moral behind story-----make question crystal clear!
2007-06-20 04:08:44 · answer #6 · answered by Como 7 · 0⤊ 0⤋
You need to clarify your clarification!
Is the first term 3/4, or (3/4)x, or (3/4)x^2, or 3/(4x), or something else?
2007-06-20 01:03:49 · answer #7 · answered by tsr21 6 · 0⤊ 1⤋
nicely, i might use Gauss-Jordan on it, and use a matrix. There are different approaches of doing this, of direction. case in point, first divide the 1st with the aid of four: [x - 2y + 2z = 6] Then, multiply the third with the aid of two: [6x + 8y - 2z = -22] upload one million and 3 at the same time: [7x + 6y + 0z = -sixteen] Multiply the third with the aid of three: [9x + 12y - 3z = -33] upload 2 and 3 at the same time: [11x + 6y + 0z = -20] look at the two in conjunction: [7x + 6y + 0z = -sixteen] [11x + 6y + 0z = -20] i p.c. to multiply the 1st with the aid of -one million: [-7x -6y + 0z = sixteen] upload the two at the same time: [4x + 0y + 0z = -4] which provides x = one million. Now, proceed this line of reasoning to locate y and z. As you already understand that z is an integer, that's in all probability much less annoying to clean up for z than for y.
2016-12-13 08:08:40 · answer #8 · answered by okamura 4 · 0⤊ 0⤋