With the following reaction: 2NO + O2 -> 2NO2?

Question

and the following data:
[O2]=(1) 0.001, (2) 0.004, (3) 0.004

[NO]=(1) 0.0001, (2) 0.001, (3) 0.003

Rate of formation of NO2=(1) 7.10, (2) 28.4, (3) 255.6

What is the rate law for this reaction?
a. rate=K[O2][NO]2
b. rate=K[O2]2[NO]
c. rate=K[O2]2[NO]2
d. rate=K[O2][NO]3

Also, what is the value for the rate constant k?
a. 510
b. 334
c. 0.293
d. 7.1 x 109

Answer 1

a. rate=K[O2][NO]2

d. 7.1 x 10^9