Algebra...help me solve this problem..?

Question

x^2+a(a-2x)=a^2+x(x-2a)



Thank you,,,GOD BLESS YOU ALL!

Answer 1

a=x or x=a

Answer 2

Your Result:
Simplify x^2+a(a-2x)=a^2+x(x-2a)

* Graphical form: x^2+a(a-2x)=a^2+x(x-2a) simplifies to x^2+a(a-2*x)-a^2-x(x-2*a)=0
* Text form: x^2+a(a-2x)=a^2+x(x-2a) simplifies to x^2+a(a-2*x)-a^2-x(x-2*a)=0
* Cartoon (animation) form: simplify_cartoon( x^2+a(a-2x)=a^2+x(x-2a) )
simplify_cartoon( x^2+a(a-2x)=a^2+x(x-2a) )

Detailed explanation:
Look at x^2+a(a-2*x)=highlight_red( a^2+x(x-2*a) ).
Moved these terms to the left highlight_green( -a^2 ),highlight_green( -x(x-2*a) )
It becomes x^2+a(a-2*x)-highlight_green( a^2 )-highlight_green( x(x-2*a) )=0.
Result: x^2+a(a-2*x)-a^2-x(x-2*a)=0

Done!

Answer 3

Start by multiplying it all out:

x^2 + a^2 - 2ax = a^2 + x^2 - 2ax

Then collect like terms, changing the sign as we move them across the equal sign.

x^2 - x^2 -2ax +2ax = a^2 - a^2

or

0 + 0 = 0

Therefore, your equation will be true for ANY choice of a and x. ALL numbers satisfy it!

Answer 4

x^2 + a(a - 2x) = a^2 + x(x - 2a)

x^2 + a^2 + - 2ax = a^2 + x^2 - 2ax

The terms on both sides are equal.

Answer 5

x^(2)+a(a-2x)=a^(2)+x(x-2a)

Multiply x by each term inside the parenthesis (x-2a).
x^(2)+a(a-2x)=a^(2)+(x(x)+x(-2a))

Complete the multiplication of x by each term inside the parenthesis.
x^(2)+a(a-2x)=a^(2)+(x^(2)-2ax)

Remove the parenthesis around the expression x^(2)-2ax.
x^(2)+a(a-2x)=a^(2)+x^(2)-2ax

Multiply a by each term inside the parenthesis (a-2x).
x^(2)+(a(a)+a(-2x))=a^(2)+x^(2)-2ax

Complete the multiplication of a by each term inside the parenthesis.
x^(2)+(a^(2)-2ax)=a^(2)+x^(2)-2ax

Remove the parenthesis around the expression a^(2)-2ax.
x^(2)+a^(2)-2ax=a^(2)+x^(2)-2ax

Move all terms not containing x to the right-hand side of the equation.
x^(2)+a^(2)-2ax-x^(2)+2ax=a^(2)

Since x^(2) and -x^(2) are like terms, add -x^(2) to x^(2) to get 0.
0+a^(2)-2ax+2ax=a^(2)

Since -2ax and 2ax are like terms, subtract 2ax from -2ax to get 0.
a^(2)=a^(2)

This equation cannot be solved algebraically.
No Algebraic Solution

Answer 6

if you rewrite it, becomes

x^2 + a^2 - 2ax = a^2 + x^2 - 2ax

(x-a)^2 = (x-a)^2

1 = 1

as the equations are equal on each side, any x is possible

Answer 7

Lol i tried it kinda complicated

What grade are you in?

Answer 8

idk