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8x/3-1/6= 4(x-1)+1/4

2007-06-19 17:34:30 · 8 answers · asked by smosh 1 in Science & Mathematics Mathematics

8 answers

8x/3 -1/6 = 4x-4 +1/4
4x- 8x/3 = 4 -1/4 -1/6

(12x -8x) /3 = (48 - 3 -2) /12

4x/3 = 43/12
4x = 43/4
x = 43/16

2007-06-19 17:38:09 · answer #1 · answered by sweet n simple 5 · 1 2

8x / 3 -1 / 6 = 4 ( x-1 ) + 1 /4
(16 x - 1 ) / 6 = [ 16 (x - 1) + 1 ] / 4 . . . . . cancel the 2 in denominator
32 x - 2 = 48 ( x - 1) + 3 . . . cross multiply
32 x - 2 = 48 x - 48 + 3
16 x = 43
x = 43 /16

2007-06-20 00:46:53 · answer #2 · answered by CPUcate 6 · 0 0

Solving for X?

8x/3-1/6= 4(x-1)+1/4

multiply through by 12 since that will eliminate 3 fractions

32x - 2 = 48(x-1) + 3

multiply 48 times the contents in the parens.

32x - 2 = 48x - 48 + 3

subtract 32x from both sides of the equation

-2 = 16x - 45

add 45 to both sides

43 = 16x

divide both sides by 16

x = 43/16 = 2 11/16

2007-06-20 00:44:10 · answer #3 · answered by jimschem 4 · 0 1

8x/3 - 1/6 = 4(x-1) + 1/4
8x/3 - 1/6 = 4x - 4 + 1/4
8x/3 = 4x - 4 + 5/12
8x/3 = 4x - 43/12
-4x/3 = -43/12
x = (-43/12)(-3/4) = 43/16 ~ 2.6875

2007-06-20 00:47:31 · answer #4 · answered by abernanit 1 · 0 0

8x/3-1/6= 4(x-1)+1/4

8x/3-1/6=4x-4+1/4

8x/3-4x= -4+1/4+1/6

-4x/3 = (-96+6+4)/24

-4x/3 = -84/24

x= -84*3/(24*-4)

x=21/8

2007-06-20 00:45:15 · answer #5 · answered by Anonymous · 0 0

well first try to simply things:

8x/3 -1/6 = 4x -4 +1/4...now try to get rid of fractions

multiply both side by 6:

16x - 1 = 24x -24 + 6/4....now to get rid of other fraction, mulitply by 4

64x - 4 = 96x -96 +6....now bring x-s to one side, and the numbers to the other:

86 = 32x, x = 43/16

2007-06-20 00:42:54 · answer #6 · answered by Robert C 3 · 0 2

X by 12
32x - 2 = 48x - 48 + 3
16x = 43
x = 43 / 16

2007-06-20 06:15:13 · answer #7 · answered by Como 7 · 0 0

8x/3-1/6= 4(x-1)+1/4(12)
32x-2=48(x-1)+3
32x-2=48x-48+3
43 = 16x
x = 43/16

2007-06-20 00:40:42 · answer #8 · answered by bourqueno77 4 · 0 3

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