Find the value of the standard normal random variable z, called z(sub)0 [z_0] such that:
P(z (is less than or equal to z_0 ) = 0.6279
I got z_0: .325 by looking up value on a chart.
P(-z_0 less than or equal to] z [less than or equal to] z_0 ) = ?
Not sure how to go about this, tried about a million different ways.
Also,
P(-z_0 [less than or equal to] z [less than or equal to] 0 ) = 0.2671
z_0 =
2007-06-19
16:51:16
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3 answers
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asked by
hamncheeser
2
in
Science & Mathematics
➔ Mathematics
That should say,
P(-z_0 less than or equal to] z [less than or equal to] z_0 ) = .3272
2007-06-19
17:03:55 ·
update #1
Thanks for the help; I'm beginning to the think the programming of the website has some sort of error on this problem.
2007-06-19
17:18:42 ·
update #2