Is this reaction balanced?

Question

Ba+AlCl3----------> 1 BaCl2+ Al

Answer 1

No
It would be:
3Ba(2+) + 2AlCl3 ---> 3BaCl2 + Al(3+)

Answer 2

in this equation you have
on the product side
1 Ba
1Al
3Cl
on the reactant side
1Ba
1Al
2Cl
This can't be right because you don't have equal numbers for EACH AND ALL element on both sides (3Cl on product versus 2Cl reactant)
If the teacher or book gave you the subscripts ( example - little 3 after the Cl on product side and little 2 after the Cl on the reactant side) then you know that these are accurate and you don't change them at all. That only leaves changing the coefficients (number before the element/molecules)

to balance - step one
list each element on the product side and reactant side like I did above to see what is definitely off. In this case you need more Cl on the right or reactant side. The # 1 that you put in front of the BaCl2 doesn't change anything since anything that doesn't have a number at all in front of it is an invisible1.
Since you new, you would probably put a 2 where you had written the 1 for a formula of

Ba + AlCl3 --> 2 BaCl2 + Al

this gives you now
on the product side
1 Ba
1Al
3Cl
on the reactant side
2Ba
1Al
4Cl (2 coefficient times 2 subscript)

you start to develop an eye for what needs to be done ( you might notice that Cl3 and Cl2 have 6 as the LCD). Leave the individual elements for last since you can put any number coefficient on them that is needed. the next thing would be to get the Cl to have equal numbers.

Ba + 2 AlCl3 --> 3 BaCl2 + Al

on the product side
1 Ba
2Al
6Cl (2 coefficient times 3 subscript)
on the reactant side
3Ba
1Al
6Cl

now you need to get 3 Ba on the product side and 2 Al for the reactant side

3 Ba + 2 AlCl3 --> 3 BaCl2 + 2 Al

on the product side
3 Ba
2Al
6Cl
on the reactant side
3Ba
2Al
6Cl

Each and every element on both sides of equation match so you know you are balanced - hope i at least helped a little instead of confusing you more -

good luck

Answer 3

You have 1 Ba on each side...so the Ba is balanced.
You have 1 Al on each side, so the Al is balanced.
You have 3 Cl on the reactant side, but only 2 Cl on the product side. Clearly the reaction is not balanced.

What if you started with 2 AlCl3 and ended with 3 BaCl2?
Can you balance the Ba and the Al now? Go ahead ans do it.

Answer 4

A balanced equation requires that the same number of atoms of each element are present on both sides of the equation. This is the Law of Conservation of Mass.

Your equation is not balanced. Start with the chlorine atoms. The common factor between 2 and 3 is 6. Use this hint and you are almost done.

Answer 5

No it should be 3Ba + 2AlCl3 ----------> 3BaCl2 + 2Al.
So on both the products and reactants side there are 3 Ba, 2 Al, and 6 Cl. =)

Answer 6

no because the Cl is not balanced. 3 on one side and 2 on the other.
3Ba + 2AlCl3 -------> 3BaCl2 + 2Al

Answer 7

3Ba + 2AlCl3 --> 3BaCl2 + 2Al

Answer 8

oh fun chemistry...enjoyed that so much better than taking physics right now...it isn't balanced

Answer 9

3Ba + 2AlCl3 ---------> 3BaCl2 + 2Al