e^(pi)i = -1?

Question

That is all know anything significant to that.

to the guy who said it was wronge no it is right I just used parenteses to show pie was one variable

I was borde and typing things in my caculator.

Answer 1

e^(ix) = cos x + i sin x

If x = π

then

e^(iπ) = cos π + i sin π = -1

Since
cos π = -1
sin π = 0
.

Answer 2

This is Euler's famous equation, but you have it slightly wrong.

It should be
e ^ (pi * i) = -1

The best way to think of it is a rotation on a unit circle drawn on the complex number plane. The horizontal axis is the real numbers, and the vertical axis is the imaginary numbers. You begin normally, on the right-most point on the circle, a value of 1. If you move pi radians around the circle, you'll be on the opposite side, or -1.

If you only moved pi/2 radians, you'd be at the top of the sphere, with an imaginary component (i), but no real component:
e^(pi/2 * i) = i

If you moved 3/2*pi radians, you'd be at the bottom:
e^(3/2*pi * i) = -i

Answer 3

This is Euler's Identity.
See http://en.wikipedia.org/wiki/Euler's_identity
for why some think this is the greatest equation ever.

Answer 4

is that a new language?