in the math equation y= (x-3)(x-4), how do you identify the "zeroes"?

Answer 1

zeros are x ints, set y=0
(x-3)=0 and (x-4)=0
x=3 x=4

Answer 2

You say a number is a "zero" of the equation,

if when you substitute the number to x,

then you will get y = 0.

Therefore,

in your equation, 3 is a "zero" because:
y = (3 - 3)(3 - 4)

y = (0)(-1)

y = 0

and, 4 is also a "zero" because:
y = (4 - 3)(4 - 4)

y = (1)(0)

y = 0

Therefore, the "zeroes" of the math equation y = (x - 3)(x - 4) are 3 and 4.

Answer 3

The "zeroes" of a function are where that function is equal to 0.

Here, y is a function of x. So set y = 0 and solve for x.

0 = (x-3)(x-4)

You can quickly see that if you plug in 3 or 4, the equation will be true (0 = 0).

0 = (3 - 3)*(3 - 4) = 0 * (-1) = 0

(0 = (4 - 3)*(4 - 4) = (1) * 0 = 0

Answer 4

the zeroes are the x-intercept

to find x intercept, plug 0 for y

0 = (x - 3) (x - 4)
x = 3 or 4


the zeroes are 3 and 4

Answer 5

The "zeroes" are the x-intercepts. If you set y equal to zero, then (x-3) should equal zero. If (x-3) is equal to zero, then x would have to be 3. Therefore, the parabola would intersect the x-axis at (3,0)

Repeat for (x-4)

Answer 6

It means, when is y zero?

For any two things to multiply to zero, at least one must be zero itself.

So you need x-3 to be equal to zero, and/or x-4 to be equal to zero.

So x must be 3 or 4.

Answer 7

y=(x-3)(x-4)
x-3=0 ---->x= 3

x-4=0 ----->x=4
Good Luck!

Answer 8

Don't know the answer to the math but we should talk...Estreet & ragesteen...what a hoot! LOL!

Answer 9

y = 0 when x = 3 and x = 4
ie curve cuts x axis at (3,0) and (4,0)
Curve cuts y axis when (-3).(-4) = 12
ie cuts y axis at (0,12)