1.
If the perimeter is 44 and one side is 10, the figure must be a rectangle, not a square.
Let the unknown side be length x.
Then:
2(x + 10) = 44
Dividing by 2:
x + 10 = 22
Subtracting 10:
x = 12.
The area is the product of the lengths of the two unequal sides.
That is 10*12 = 120.
2.
If the base is b yd., and the adjacent side is 12yd, then the area 96yd^2 satisfies:
12*b = 96
Dividing by 12:
b = 96/12 = 8.
The side labelled b is 8yd.
2007-06-19 12:25:52
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answer #1
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answered by Anonymous
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Your first question has some contradictory information. Squares have four sides of equal length. If one side of a square measures 10 units in length, then so do the other three. Perimeter is the length around the shape, so the perimeter of the square would be:
10+10+10+10 = 40, not 44.
I think that you have a RECTANGLE, not a square. Its perimeter is 44, so
length + width + length + width = 44
length + 10 + length + 10 = 44
length + length = 24
length = 12
The area of a rectangle is found by multiplying the length times the width:
A = 12 * 10
A = 120
In your second question, the length of the rectangle is 12 yd, and its area is 96 yd^2, so
A = length * width
96 yd^2 = 12 yd * width
(96 yd^2)/(12 yd) = (12 yd * width)/(12 yd)
8 yd = width
Then
P = 12 yd + 8 yd +12 yd + 8 yd
P = 40 yd
I hope that all of this is clear!
2007-06-19 12:27:34
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answer #2
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answered by math guy 6
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well, I think that maybe there was a typo on the first problem, because you would have to divide the perimeter by 4 to find the side of a square... and that would be 11, not 10. If you use 11, the area of the square is 121.
for the second question, you would use a=bh which would be 96=12b and that means b=8. Plug it back into the perimeter formula p=2L+2W p=2(12)+2(8) p=24+16 p=40
2007-06-19 12:26:06
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answer #3
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answered by Ashley S. 1
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ok
L times W= area L is length and W is width. So you would do 10 times 10 but that makes no sence because to find perimeter you would add all the sides so it should be 40 and i think you would do 2x+2y= permeter for a rectsangle so the area is 96 so what times what equals 96. 96 divided by 12 is 8 so 2 times 12 plus 2 times 8 that would be 24 plus 16 so 40 would be perimeter and i how you are young because im 13 and this is ez and i sux at math
2007-06-19 12:25:08
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answer #4
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answered by Anonymous
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Area = LxW
If the perimeter is 44, then L is 10 and W is 12, your area is 120.
2nd question: 96/12=b =8
perimiter is the sum of all sides so 8+8+12+12=40
2007-06-19 12:20:12
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answer #5
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answered by ☆Zestee☆ 5
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If the perimeter is 44 then the side is 44/4 = 11, not 10.
The area is 11² = 121 un²
I actually don't even know what you're asking exactly. Copy the problems down correctly.
2007-06-19 12:21:16
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answer #6
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answered by MathGuy 6
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If it is a square then the measurement cannot be 10 if the perimeter is 44.
Area= length X width
If perimeter is 44, then each side is 11.
Area= 121
I may be wrong, but that is my understanding????
2007-06-19 12:30:40
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answer #7
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answered by bayoubelle24 5
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You have stated an impossibility that 11=10. <-- 1st problem
The dimensions of the rectangle must be 12 *8 = 96 yds ^2
So the perimeter is 2*12+2*8 = 40 yds
2007-06-19 12:27:16
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answer #8
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answered by ironduke8159 7
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Either the perimeter equals 44
or
the side of the square is 10
but not both.
2007-06-19 12:19:31
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answer #9
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answered by Anonymous
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With a sq. each area is comparable to all the different facets, so if one area is 3x+4 all the different facets are equivalent to 3x+4. because of the undeniable fact that's a sq. you could purely multiply via 4 to get the respond, which for that reason is 12x+sixteen.
2016-12-08 13:56:49
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answer #10
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answered by blea 4
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