i need help.find the slopeand y-intercept of the lne that passes through 2,4)and (4,6)?

Answer 1

Calculating the slope:

slope = (y2 - y1)/(x2 - x1)
slope = (6 - 4)/(4 - 2)
slope = 2/2
slope = 1

Now that you have the slope, you can plug in either point into slope-intercept form to get the Y-intercept:

y = mx + b
y = 1*x + b

4 = 1*2 + b
2 = b

The equation for the line is: y = x + 2.

Slope = 1
Y-intercept = 2

Answer 2

To find slope: y2-y1 over x2-x1(numbers behind x and y are to specify which number in the co-ordinates to subtract)
~6-4= 2
~4-2=2 (slope wound be 2 over 2 or 1)
Sorry I don't really remember how to do y-intercept.

Answer 3

To find the slope and y intercept you have to use the formula y=mx+b. b=-2 so now the formula is y=mx-2 now we figure that m=1 because you have to go down two units and over two units to get to the point 2,4. so now the formula is y=x-2
the slope is 1 and the intercept is 2

Answer 4

slope= (y1-y2)/(x2-x1)

(4-6)/(2-4)=-2/-2=1

slope=1

y intercept is found by saying 1 point (2,4) and another point (0, ?) the reason x is zero is because y intercept is on the y axis meaning x is zero

we know slope=1

(4-?)/(2-0)=1

(4-?)/2=1

Corssmultiply and get

(4-?)=2

?=2

Slope=1
Y-intercept=2

Answer 5

4-6
-----
2-4

-2
---
-2

m=1

(x,y) = (4,6)

y=mx+b

6=1*4 +b

6= 4 + b

b=2

y=x+2

Answer 6

slope=
y2-y1
---------
x2-x1

6-4 over 4-2

2 over 2

slope=1