Reaction for the electrolysis of potassium iodide solution using platinum electrodes. 2H2O + 2I gives H2+2OH?

Question

a)what is the anode reaction in this electrolytic cell?
b) What process occurs at the anode of an electrolytic cell while the cell is opening
Q2. state whether the change of NH3 to dinitrogen oxide N2O is an oxidation/ reduction?

Yap I made a mistake in the equation..
2H2O + 2 I gives I 2+ H2 + 2OH

Answer 1

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Answer 2

Electrolysis Of Potassium Iodide

Answer 3

i am not sure but the symbol equation you gave has to be wrong because there is 2l on one side and no l on the other also there are too many hydrogens on one side than the other! remember to blance the equation!

Answer 4

+ electrode: 2I- -----> I2 + 2e- (oxidation)

- electrode: 2H+ + 2e- ----> H2 (reduction)

NH3 to N2O is oxidation.