Solve for x.
3x/4=7-x/3
The Forward Slash is a fraction bar. The problem should read 3x over 4 equals 7 minus x over 3
2007-06-19 07:50:00 · 6 answers · asked by D-Man 1 in Education & Reference ➔ Homework Help
If the 7 - x is all over 3, then it should have brackets round, and be written:
3x / 4 = (7 - x) / 3.
If that is correct, then proceed as follows:
Multiply by 12:
9x = 4(7 - x)
Expand the brackets:
9x = 28 - 4x
Add 4x to each side:
9x + 4x = 28
(9 + 4)x = 28
13x = 28
Divide by 13:
x = 28/13.
2007-06-19 08:08:22 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I would cross multiply to get rid of fractions:
3x......7 - x
--- = ----------
4...........3
(3x)(3) = (4)(7 - x)
to get
9x = 28 - 4x
then add +4x to both sides to get
13x = 28
then divide both sides by 13 to get
x = 28 / 13
* Check your work
plug x = 28 / 13 back into
original equation:
3[28/13]/4 is the same as 3[7/13] or 21/3
[7-28/13]/3 is the same as [63/13]/3 or 21/3
so this looks correct.
2007-06-19 09:53:27 · answer #2 · answered by Nghiem E 4 · 0⤊ 0⤋
my basic math could be off but it should look something like this by step
3x/4=7-x/3
3x=28-4x/3 (mutlipy by 4)
9x=84-4x (multipy by 3)
9x+4x=84
13x=84
x=84/13
2007-06-19 08:03:23 · answer #3 · answered by Tu N 2 · 0⤊ 0⤋
x=84/13
2007-06-19 08:02:34 · answer #4 · answered by Bert C 7 · 0⤊ 0⤋
not sure what you mean by utilising 'algebraic fractions'. Do you basically decide to remedy the equation the place this = 0? Or factorise this? Or... use long branch? Please make clean the question.
2016-11-06 22:52:21 · answer #5 · answered by ? 4 · 0⤊ 0⤋
3x/4=7-x/3
3x/4+x/3=7
(9x+4x)/12=7
13x/12=7
13x=84
x=84/13
2007-06-19 08:00:10 · answer #6 · answered by cidyah 7 · 0⤊ 0⤋