Can you solve this math problem?

Question

Kris and Moira together have nine beans.
If Jay and Moira put their beans together,they'd have eleven beans. Afrin and Jay have sixteen beans when they put their beans together. the four kids have a total of 25 beans. Kris and Jay,together have the same number as erin Kris and torn have a total of fourteen beans between them.
no two kids have the same number of beans erin and moira have fifteen together

Answer 1

k+m = 9
j+m =11
A+j = 16
a+k+j+m=25
k+j=e
k+t=14
e+m=15

Now, what's the question ?????????

Answer 2

I don't understand. Your question refers to "the four kids", but includes Afrin, Jay, Kris, Moira, Erin and Torn.

It would also help if you would be careful when you type so that you avoid run-on sentences such as "Kris and Jay, together have the same number as erin Kris and torn have a total of fourteen beans between them."

Please try restating your question.

Answer 3

Just alot of book keeping. You can form equations for each statement. For example
"the four kids have a total of 25 beans" is
A+J+K+M=25; each variable is the first letter of each kid's name. Also K+J=E (Kris and Jay, together, have the smae number as Erin). Then A+E+M =25. Since E+M = 15, A=10, J=6, M=5, K=4