Explain and discuss the reaction of :CuSO4∙oH20 and CuSO4∙5H2O?

Question

Explain and discuss the reaction of :CuSO4∙oH20 and CuSO4∙5H2O? What is the delta H? What is the q=.What is the mass values?

Table 1.1: title
Given:0.783 M
CuSO4  10g
M1 H2O80mL
Ti22.20 ºC
Tf32.60 ºC
ΔT10.4 ºC
ΔH= (q / # moles)(-435.24) / (0.0626)= -6952.7g
Q= -mass x (4.184 J K-1g-1) ΔT

( -10g)(4.184 J K-1g-1 )( 283 K) =

Table 1.2: title
Given:0.5 M
CuSO4 ∙ 5H20 10g
M1 H2O80mL
Ti22.85 ºC
Tf21.40 ºC
ΔT-1.45 ºC
ΔH= (q / # moles)(60.7) / (0.0400)= 1516.7
Q= -mass x (4.184 J K-1g-1) ΔT

( -10g)(4.184 J K-1g-1 )( 271.55K ) =

Table 1.3: title
Given:0.626 M
CuSO4  5g
M1 H2O50mL
Ti-22.40 ºC
Tf-34.40 ºC
ΔT12.0 ºC
ΔH= (q / # moles)(-251.0) / (0.0313)= 1516.7
Q= -mass x (4.184 J K-1g-1) ΔT

( -5g)(4.184 J K-1g-1 )( 285K ) =

Table 1.4: title
Given:0.4 M
CuSO4 ∙ 5H20 5g
M1 H2O50mL
Ti23.55 ºC
Tf22.05 ºC
ΔT-1.5 ºC

Answer 1

Discuss ????????? This is an experimental problem. Do the experiment first !!!!!!!!!!