(-3x^3/6x^-2)^-1
Detailed answer please! Thanks!
2007-06-19 05:16:55 · 6 answers · asked by Tony 1 in Science & Mathematics ➔ Mathematics
(-3x^3/6x^-2)^-1
= 1/(-3x^3/6x^-2)
= (6x^-2)/(-3x^3)
= -2x^(-2 - 3)
= -2x^-5
2007-06-19 05:27:57 · answer #1 · answered by topsyk 3 · 0⤊ 0⤋
I don´t know if I understood your question, but I think this:
-3x^3/6x^-2 = (-1/2) *(x^5), so
(-3x^3/6x^-2 )^-1 = - 2 /x^5.
Bye.
2007-06-19 12:25:27 · answer #2 · answered by infty 3 · 0⤊ 0⤋
This is a simplification exercise. So you start with the innermost part of the expression. The x^-2 term can be moved to the numerator by virtue of the reciprocal relation. Then we have
(- 3 x^3 x^2/6 )-1.
We can combine "x" terms and divide out 3 by 6 to get
(- x^5 /2)-1.
We can again use the reciprocal relation to get
- 2/x^5
2007-06-19 12:24:49 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
Assuming the question is:
[(-3x^3) / (6x^-2)]^-1
This is like:
[(-3x^3)*(x^2 / 6)]^-1
= (-3x^5 / 6)^-1
= (-x^5 / 2)^-1
= -2 / x^5
2007-06-19 12:22:22 · answer #4 · answered by Math Stud 3 · 0⤊ 0⤋
(-3x^3/6x^-2)^-1 = (6x^-2/- 3x^3)
= -2x^-2 - 3
= -2x^-5
2007-06-19 12:23:47 · answer #5 · answered by Tubby 5 · 0⤊ 0⤋
(-3x^3/6x^-2)^-1
(-3(x^3)(x^2)/6)^-1
(-x^5/2)^-1
-2/x^5
2007-06-19 12:23:16 · answer #6 · answered by yeeeehaw 5 · 0⤊ 0⤋