please anyone help..;;(Chem question)?

Question

this is the question I can't figure it out please help me out;;

How many milliliters of concentrated (12M) hydrochloric acid are required to react completely with 10ml of 2-methly-2-propanol?

I really appreciate for all answers. thank you very much.

Answer 1

the density of 2-methyl-2-propanol is .78g/ml
10 ml * .78 g/ml = 7.8 g
7.8 g / 74.12 g/mol = .105 mol

therefore need .105 mol of HCl
= .105mol/12mol/L = .0088 L
8.77 ml needed.

Answer 2

You are suppose to know the the molarity of the 2methly 2 propanol if not then do the titration and by using the formula N1V1=N2V2 you can find out the volume but you need to know the molarity of 2methy2 propanol.

Answer 3

If the isobutyl alcohol is pure, you need to have its density. Then you can compute the grams of the alcohol. Call that G. Compute the mole wt, call that MW. Then find the moles of the alcohol from
G/MW, call that Mal.

The reaction is that the alcohol is converted to a chloride, while water is formed. The reaction involves a 1 to 1 reaction of HCl with the alcohol. Then Mal = Mhcl, the moles of HCl.
To find the ml (V) of the 12 M HCl, use the relation
0.012*V = Mhcl. The conversion is needed to get results in mL when the molarity is in moles/L.

Answer 4

To answer at this question I have to know the molarity of 2-methyl-2- propanol

*****OH*********************Cl
CH3C CH3 + HCl >> CH3C CH3 + H2O
*****CH3********************CH 3

From Molarity of 2-methyl- 2- propanol we get moles :
moles = M x V ( in L )
moles 2- methyl - 2 propanol = moles HCl
L of HCl needed for the reaction = moles / M = moles / 12
Convert L in mL and yuo have the answer

Answer 5

Depends on the pKb value.