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x^2 - 6x + 8.............x^2 - 15x + 56
------------------...*... ---------------------
x^2 - 17x + 56......... x^2 - 15x + 44

2007-06-19 04:36:37 · 4 answers · asked by lexisayn 1 in Science & Mathematics Mathematics

So far no one is correct.

The answer should be
(x-2)(x-8)
--------------
(x-10)(x-11)

I can't seem to get to this answer???

2007-06-19 05:02:29 · update #1

No wonder I typed it wrong.

x^2-6x+8..........x^2-15x+56
------------------*------------------
x^2-17x+70.....x^2-15x+44

SORRY

2007-06-19 05:08:08 · update #2

4 answers

Factor:

[(x-4)(x-2)] / [(x-9)(x-6)] * [(x-8)(x-7)] / [(x-11)(x-4)]

Cancel the x-4 terms:

[(x-2)(x-8)(x-7)] / [(x-9)(x-6)(x-11)]

2007-06-19 04:42:01 · answer #1 · answered by yeeeehaw 5 · 0 1

(x-2)(x-8)(x-7)
------------------
(x-11)(x^2-17x+56)

I can't see how "x^2-17x+56" can reduce at all.

If the answer should be:

(x-2)(x-8)
-------------
(x-10)(x-11)


then the original problem was mis-written. The first fraction should've read:

x^2-6x+8
-------------
x^2-17x+70

2007-06-19 12:04:21 · answer #2 · answered by Eddie A 1 · 0 0

^2 - 6x + 8.............x^2 - 15x + 56
------------------...*... ---------------------
x^2 - 17x + 70......... x^2 - 15x + 44

= (x-2)(x-4)/[(x-10)(x-7)] *(x-8)(x-7)/[(x-4)(x-11)]
The (x-4) and (x-7) terms cancel, so we get:
(x-2)(x-8)
-----------------
(x-10)(x-11)

2007-06-19 12:10:30 · answer #3 · answered by ironduke8159 7 · 0 0

x^2 - 6x + 8.............x^2 - 15x + 56
------------------...*... ---------------------
x^2 - 17x + 56......... x^2 - 15x + 44

(x^2 - 4x - 2x + 8)(x^2 - 8x - 7x + 56)
-------------------------------------------------
(x^2 - 4x -14x + 56)(x^2 -11x - 4x + 44)

(x(x - 4) - 2(x - 4))(x(x - 8) - 7(x - 8))
------------------------------------------------
(x(x - 4) - 14(x - 4))(x(x - 11) - 4(x - 11))

(x - 4)(x - 2)(x - 8)(x - 7)
--------------------------------
(x - 4)(x - 14)(x - 4)(x - 11)


(x - 2)(x - 8)(x - 7)
-------------------------
(x - 14)(x - 4)(x - 11)

2007-06-19 11:55:45 · answer #4 · answered by topsyk 3 · 0 1

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