Solve the following equations ³√x² = 9
2007-06-19 01:00:45 · 9 answers · asked by alesia h 1 in Science & Mathematics ➔ Mathematics
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2007-06-19 01:04:12 · answer #1 · answered by xprof 3 · 0⤊ 1⤋
x = 27
2007-06-19 08:09:37 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Start by cubing each side to get rid of the cube root sign:
x^2 = 9^3
Now take the square root of each side:
x = 9^(3/2) = [9^(1/2)]^3 = 3^3 = 27
Notice that your first expression is really x^(2/3) and that you can solve in one step by raising both sides to the (3/2).
2007-06-19 08:06:01 · answer #3 · answered by MathProf 4 · 0⤊ 0⤋
x^2 = 9^3 =729
so x = 729^0.5 = 27
2007-06-19 08:08:28 · answer #4 · answered by raisin76 1 · 0⤊ 0⤋
x^(2/3) = 9
x = 9^(3/2)
x = 3³
x = 27
2007-06-19 14:55:47 · answer #5 · answered by Como 7 · 0⤊ 0⤋
it is the same as x^(2/3) = 9
x=9^3/2
x=(+/-3)^3
x=+/-27
x = 27 or x = -27
2007-06-19 08:04:28 · answer #6 · answered by geloi 2 · 0⤊ 0⤋
cube both sides first, x^2=729, then square root both sides, x=27, technically it would be +27 and -27
2007-06-19 08:04:45 · answer #7 · answered by hrhbg 3 · 1⤊ 0⤋
so cubing on both sides we get
x ^ 2 = 729
which gives x = +- 27
2007-06-19 08:03:58 · answer #8 · answered by yashtapmi 2 · 1⤊ 0⤋
cube both sides
x^2 = 729 now take the sqrt of both sides
x = 27
2007-06-19 08:03:36 · answer #9 · answered by jeremy s 2 · 1⤊ 1⤋