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Refer to the data presented in the accompanying pressure-versus-volume graph. When a system changes from A to B along the path shown, it gains 2890 J of heat. What is the change in internal energy of the system?

http://edugen.wiley.com/edugen/courses/crs1507/art/qb/qu/c15/ch15p_14.gif

2007-06-18 22:55:20 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

The change of internal energy is the sum of work done at the system W plus heat transferred Q:
ΔU = W + Q

where the work is
W = - ∫ p dV
In the sketch you have only two types of changes:
- vertical path
p changes and V is constant. Thus the work for this sections equals zero
- horizontal path
V changes and p is constant. Thus the work for this sections is W = - p · ΔV

Therefore
W = - 10·10⁴ Pa · 12·10⁻³ m³ - 15 · 10 ⁴ Pa · 12·10⁻³ m³
= -3000J
and

ΔU = -3000J + 2890J = -110J

2007-06-18 23:28:08 · answer #1 · answered by schmiso 7 · 1 0

That link takes me to the Wiley Plus log in page. It doesn't show the graph.

2007-06-19 06:28:30 · answer #2 · answered by Swamy 7 · 0 0

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