6x+4x=y
(the 6 and 4 are from above)
10x=y
y=volume of pool
2007-06-18 17:56:45
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answer #1
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answered by haley 2
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Ah, the old swimming pool drain problem. The key to doing these is to remember that
Volume = volume/time * time.
We use "pool" as a unit of volume.
So, for valve 1alone, Pool = pool/4 * 4 hours
and valve 2 alone, Pool = pool/6 * 6 hours.
In this problem we have TWO valves running for x number of hours.
So: 1(pool) = 1/4 x + 1/6 x = 5/12 x. Then it takes 12/5 hours or 2.4 hours to drain the pool.
2007-06-18 18:01:30
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answer #2
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answered by cattbarf 7
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First lets assume that the pool capacity is of x liters.
Then the drain speed of each valve is of:
x liters each 4 hours for the first
x liters each 6 hours for the second
To find the total time to drain x liters we just add both speeds, it is:
x (l/4h) + x (l/6h) = ¼ + 1/6 (x*l/h) = 5/12 (x*l/h) which means that both valves drain 5/12 of the pool each hour.
Therefore it will take 12/5 = 2.4 hours to drain the whole pool.
2007-06-18 18:10:42
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answer #3
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answered by Dexter H. 2
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Assume the volume of the pool is x gallons. The first valve drains at x/4 gallons per hour. The second drains at x/6 gallons per hour. So, together they drain x/6 + x/4 gallons per hour
2x/12 + 3x/12 = 5x/12 gallons per hour. That means they would drain x gallons in 12/5 hours or 2 hours and 24 minutes.
2007-06-18 18:02:03
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answer #4
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answered by Anonymous
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consider the valve's rates
the first valve empties 1/4 pool/hour
second 1/6
working together, they rmpy 1/4 + 1/6 = 5/12 pool in an hour, so they empty the whole pool in 12/5 hours
= 2 hours, 24 minutes.
2007-06-18 18:01:55
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answer #5
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answered by holdm 7
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Let x = time the 2 valves can drain the pool
1/4x = the rate of the first valve
1/6x = the rate of the second valve
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1/4x + 1/6x = 1
Multiply the equation by 12
3x + 2x = 12
5x = 12
x = 12/5
x = 2.40 hours or 2 hours and 24 minutes
2007-06-18 18:12:48
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answer #6
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answered by detektibgapo 5
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I have no steps since I did it in my head, but I believe the answer is two and a half hours...
2007-06-18 17:57:48
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answer #7
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answered by Walter . 2
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Speed is the same as that which I thought to answer the question
2007-06-18 18:00:37
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answer #8
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answered by a4tech2030 1
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2.44 hours
I think you should find out how to solve it yourself.
2007-06-18 18:00:19
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answer #9
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answered by utah-1992 1
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