A .200-m uniform bar has a mass of .750 kg and is released from rest in the vertical position. The spring is initially unstrained and has a spring constant k=25.0 N/m. Find the tangential speed with which end A strikes the horizontal surface.
The drawing shows three distance all equalling .100m ad there being a pivot that is frictionless. A is labeled where the horizontal distance.
Not sure if this is enough description of the picture or not!
2007-06-18 15:00:14 · 1 answers · asked by wildcherrychica1 2 in Science & Mathematics ➔ Physics
A picture would help.
It sounds like using conservation of energy will work since there is friction.
The center of mass of the rod will lose m*g*.1m of potential energy in the fall. The spring will compress to gain stored energy of .5*k*x^2
where x is the compression distance. Need the diagram to figure that.
The balance will be in kinetic energy. You can use translational or rotational reference frame to compute.
j
2007-06-19 11:58:06 · answer #1 · answered by odu83 7 · 0⤊ 0⤋