help help help help please?

Question

This is a statistics problem. Please explain as you're solving. thanks very much

A test has 5 True/False questions, 4 Multiple Choice questions with 4 options, and 6 Always-Sometimes-Never questions. How many different ways can this test be finished?

Answer 1

Take each set of questions and multiple the number of questions by the number of answers, and multiply the three together.

5 X 2 = 10 (True or false)
4 X 4 = 16 (Multiple Choice)
6 X 3 = 18 (Always/Sometimes/Never)
Total = 2880

Answer 2

Do you mean: How many ways are there of
answering all the questions?
If so, Yoda's answer is wrong.
If a test has 5 True/False questions there are 32
possible ways or 2^5 ways to complete this part of the test.
Why? Build it this way.
On a 2 question T/F test
the possibilities are
TT TF FT and FF
To get all the possibilities for a 3 question T/F
test, put a T after each of these and then an F:
TTT TFT FTT FFT TTF TFT FTF FFF.
Now do this for 4 and 5 question T/F tests
and you will find 32 possibilities for the 5
question T/F test.
Similarly there are 4^4 ways to do the multiple choice
questions and 3^6 ways to do the always-sometimes-
never questions.
So altogether there are 32*256*729 possible test papers
or 5971968 possible test papers.

Answer 3

Only one because you still have to finish all the answers... so the only way would be to write down or choose the right answer..