How would you factor these two equations?

Question

2x^2+7x+3 and 2x^2-7x-4

Answer 1

2x^2+7x+3=2*(x+3)*(x+0.5)

2x^2-7x-4=2*(x-4)*(x+0.5)

Answer 2

(2x + 1)(x + 3)

(2x + 1)(x - 4)

A. Split up 2x^2 into (2x....)(x....)
for the first terms.
B. The last constant terms are (...+1)(...+3)
(both +positive to make + 3)
C. Then the 2x either pairs with the 1 or the 3.
Try both ways:
(2x + 3)(x + 1) does NOT work
(middle term comes out 5x instead of 7x)
Try the other way:
(2x+1)(x+3) works
(middle terms comes out 7x)

a. Split up 2x^2 into (2x....)(x....)
for the first terms.
b. The last constant terms are
(...+1)(...-4) or (...-1)(...+4)
(one must be - negative to make - 4)

c. Since you need "-7x" as your middle term,
try to get terms +1x and -8x added together

If you pair the 2x with -4 you will get -8x

So try
(2x + 1)(x - 4)
which works
(middle terms comes out 1x - 8x = -7x)

Answer 3

you have to use the quadratic equation
or
you multiply the c value by the a value then factor as normal but you have to divide the a value back out from the answer

Answer 4

Use the quadratic formula