physics problem rotational kinematics?

Question

the shaft of a pump starts from rest and has an angular acceleration of 3.00 rad/s^2 for 18.0s. at the end of this interval what is (a) the shafts angular speed and (b) the angle through which the shaft has turned?

Answer 1

♦ yes, u r less clever than lithiumdeuteride!

Answer 2

Each second, the shaft gains 3.00 rad/s in additional angular velocity, so the angular velocity after 18 seconds is:
3.00 rad/s^2 * 18 s = 54 rad/s.

To find the total angle of rotation after 18 seconds, you integrate the velocity with respect to time, from t=0 to t=18 seconds:

integral((3 rad/s)*t, t, 0, 18)
= (3 rad/s)*t^2 / 2, evaluated from 0 to 18
= 486 rad

Answer 3

a) ωf = α t = 3x18 =54 rad/s^2

b) θ = ½ α t^2 = 0.5 *3 * 18^2 = 216 radians

Answer 4

i think of you're commonly perfect, however i could say that interior the 1st occasion the tangential acceleration is nonzero, as a results of fact the direction of the tangential velocity is changing. each thing else seems perfect.