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2BN+3F2-->2BF3+N2

When 161.2g of BN are added to an excess of F2, a reaction occurs in which 326.118g of BF3 are formed.

Calculate theoretical yield of BF3 in grams.

What is meant by actual yield(formula)****

2007-06-18 13:31:09 · 2 answers · asked by m 1 in Science & Mathematics Chemistry

2 answers

The theoretical yield is the calculated amount that should be produced based on the stiochiometry. The actual yield is the amount that is actually formed and will be some amount less than the theoretical, due to by-products and other losses. You can divide the actual yield by the theoretical and get % yield.

In your problem, convert the 161.2 g of BN to moles. Mulitply by the molar ratio of 2:2 and get moles of BF3. Now multiply by the mlecular mass of BF3 and get the theoretical yield in grams of BF3.

2007-06-18 13:36:38 · answer #1 · answered by reb1240 7 · 0 0

First, write a balanced chemical equation describing the reaction: 2Na + 2HCl -> 2NaCl + H2 The equation is balanced with the aid of fact there are equivalent numbers of atoms on the two component of the "->" sign. even with the undeniable fact that, there would not ought to be equivalent numbers of molecules. What the equation additionally shows is how the molecules and atoms integrate in terms of numbers. 2 Sodium atoms integrate with 2 molecules of HCl to make 2 molecules of Salt and one million molecule of hydrogen. The ratios are 2 to 2 to 2 to one million. the magnitude of that's seen whilst the thought-approximately molarity is utilized. A mole is completely a huge style and chemists use the reality this many atoms or molecules of something has an exact weight. one million mole of Sodium atoms weighs 23 grams. that's ordinary as an atomic weight and may well be got here upon in the periodic table. Molecular weight is the sum of the atomic weights. Hydrogen has an atomic weight of one million gram in step with mole. subsequently, one million mole of H2 has a weight of two grams in step with mole. 23 grams of Sodium is what one million mole weighs. If one million atom of Sodium could make one million molecule of NaCl, then a mole of each will additionally do an identical. this suggests a one hundred% yield of NaCl would be one million mole of NaCl. NaCl has a molecular weight of 50 8.4 grams in step with mole, so that's the burden of salt generated with the aid of 23 grams of Sodium. even with the undeniable fact that, the molar ratio of Na to H2 is two to one million. this suggests a mole of Na will generate one million/2 a mole of H2. one million/2 a mole of H2 weighs one million gram.

2016-12-13 06:48:49 · answer #2 · answered by kreitman 4 · 0 0

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