English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

NH3 + 5O2 --> NO + 6H2O

If we use 6.80g of ammonia, what mass of oxygen will be required to consume all the ammonia present?

Please show explanation

2007-06-18 13:29:03 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

Yah I got 64g, but the answer key says 16g??

2007-06-18 13:41:38 · update #1

4 answers

NH3 has an atomic mass of 17 grams per mole. O2 has an atomic mass of 32 grams per mole. You have 6.8 grams of ammonia, which equals .4 moles. It takes 5 moles of O2 to bond with one mole of NH3. You have 40% of one mole of ammonia. That means you need 40% of 5 moles of O2; that equals 2 moles of oxygen. 1 moles of O2= 32 grams. 32 grams times 2 is 64 grams.

Answer: 64 grams of oxygen.

Solution:

1) find out how many moles of ammonia you have.

2) find out how many moles of oxygen you need in order to bond with all of the ammonia

3) Find out what percent of a mole you have for ammonia

4) Multiply the percent of the number of moles of ammonia by the moles of oxygen

5) Multiply the number of moles of oxygen by its atomic mass to find how many grams of oxygen you need

Hope it helps!

2007-06-18 13:45:03 · answer #1 · answered by buhsboy2007 2 · 0 0

This is a stoichiometry problem

Convert the grams of NH3 to moles by dividing by the molecular mass. Multiply by the molar ratio of 5:1 to get moles of O2. Now multiply by the molar mass of oxygen gas to get the grams of O2.

2007-06-18 13:38:49 · answer #2 · answered by reb1240 7 · 0 0

i don't know how it is possible for the answer to be 16g because i got 64g too.

2007-06-19 13:48:45 · answer #3 · answered by kiwi 2 · 0 0

huh?

2007-06-18 13:36:34 · answer #4 · answered by Anonymous · 0 1

fedest.com, questions and answers