would this be correct? can u check if im right to make sure? thanks!?

Question

link:
http://i181.photobucket.com/albums/x85/ctti_3/untitled.jpg

my answer is x=-3, 3 b/c of the open circle, right?

Answer 1

For the function to be differentiable, it must be both continuous, and as you approach the point x, the tangent lines must be continuous.

So, you are correct at x=-3 and 3 the graph is not continuous, therefore not differentiable.

However, at x=0 if also not differentiable because as you approach x=0 from the left, the slope is -1. But as you approach x=0 from the right, the slope is 2.

This is similar to the absolute value function.

So your answer would be 2. x= -3,0,3.

Answer 2

Answer is -3 , 0, 3