i need help with a pre-calculus problem.?

Question

the question says: Find the domain and range for the following function:

f(x)= The square root of: x-2

Answer 1

The domain, or set of possible x-values, must satisfy the condition that the square root is never negative. Having x greater than or equal to 2 satisfies that condition. Assuming that your square root has no plus or minus in front of it, your square root is only positive. Therefore, the range is y is greater than or equal to zero.

Answer 2

The domain of a function is the set of all numbers that the function will give a real value for if plugged in. For

f(x) = SQRT(x-2),

you know that you cannot take the square root of a negative number. Therefore, (x-2) must be greater than or equal to zero. So as long as x>= 2, you will get a real result. This is the domain of the function.

The range is all possible solutions. The lowest value of x is 2, and the greatest is infinity. When x=2, the function equals zero; when x = infinity, the function equals infinity. Therefore your range is (0, infinity)

Answer 3

Actually, the range is all >positive< reals.
The domain is all reals >=2
Since the question asks for the range of the >function< it's going to be the positive square root only. If it were both the roots, then the resulting relation wouldn't pass the vertical line test, and thus not be a function.

(Whoo! I'm gonna be teaching pre-calc next year!)

Answer 4

domain is the x values of the specific line, range is the y values. plug in the equation into your graphing calculator to see the line. i think the domain is [2, infiniti), and the range is [0, inf.)

Answer 5

y = f(x) = √(x - 2)
Domain is x ≥ 2 where x is a member of the set of Real numbers.
Range is y ≥ 0 where y is a member of the set of Real numbers.

Answer 6

range = all real #s
domain =x=>2 because if x is <2 then you get imiganry #s