an auto race is held on a circular track. A car completes one lap in a time of 1809s, with an average tangential speed of 42.6m/s. Find (a) the average angular speed and (b) the radius of the track.
2007-06-18 12:29:50 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
2pir=42.6x1809m
r=42.6x1809/2pi=12265m
w=v/r=42.6/12265=.0035rad/s
2007-06-18 13:43:52 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Angle of one lap is 2π radian.
Angular velocity = angular displacement / time
ω = θ/t
ω = 2π / 1809 = 0.003475 radian / second.
The radius of the circular path r = v / ω.
v is the linear speed.
r = v / ω
r = 42.6 / 0.003475 = 12260 m
2007-06-18 16:07:53 · answer #2 · answered by Pearlsawme 7 · 0⤊ 0⤋
The average angular speed is 2*pi/1809 = 0.000347 rad/s.
The radius is 1809 s*42.6 m/s / (2*pi) = 12265.0 m.
2007-06-18 12:41:32 · answer #3 · answered by kirchwey 7 · 0⤊ 0⤋
3.0 cm of line winding in reasons rotation of a million radian (per risk you desire to think of that 2 pi*3 reasons rotation of two pi), Angular rotation value could be stumbled on from 250/(8.4 *3) rad/s Regards - Ian
2016-10-09 11:48:18 · answer #4 · answered by Anonymous · 0⤊ 0⤋