Grade 9 Level Really HArd MAth Question?

Question

I just finished my grade 9 exam but there is a debate about 1 of the hard questions which are called Part C questions. Can u explain step by step how to get the answer. Question was

3^325
------------------
3^326 + 3^327


When i did this on the computer calculator i got 0.0833333333333 or 1/12.

Thanks for all the answers.
I jsut have a question. i did some weird way which is probably wrong. Verify id this is rite or wrong


3^125
-------------
3^126+9^126

3^125
---------
12^126


3^125
----------
36^125

1
---
12

Answer 1

OK, first, factor 3^325 out of the denominator terms, and you will get 3^325 over 3^325(3 + 3x3). The 3^325's cancel each other out, so you end up with 1 over (3 + 3x3) = 1 over 12, which is 0.08333.... OK?

Answer 2

Good question. Hopefully you know a little about the laws of exponents....because this problem requires you to work backwards a little bit. I'll show you the work, step by step:

3^325
_____________
3^326 + 3^327 (can't add exponents..must break it down)

Step 1: change 3^327 to (3^326)(3^1) -- mult. means you add exponents...

3^325
___________________
(3^326) + (3^326)(3^1)

Step 2: Hopefully you understand factoring out common factors...In the bottom of the fraction, factor out a 3^326:

3^325
______________
3^326 ( 1 + 3^1 )

Step 3: Now you can use the law for dividing powers -- subtract the exponents. 3^325/3^326 = 1/3

1
_______
3 ( 1 + 3)

1
___
3(4)

Which equals 1/12

I hope this helps. Like I said, the problem assumes you know the laws of exponents, but also how to factor....I can give more detail if you really want....

Answer 3

that is a challenging problem. There are a couple ways to do it, but let's say we can always multiply or divide every part of a fraction by the same number. Here, let's try 3^325:

3^325/3^325
---------------------------------------
3^326/3^325 + 3^327/3^325


= 1 / (3+3^2) = 1/12

Answer 4

(3^325)/(3^326 + 3^327)
= (3^325)/[3^325(3^1 + 3^2)]
= 1/(3+9)
= 1/12

Answer 5

Hard Math Questions

Answer 6

Well, 3^326 + 3^327 = 3^325(3^1 + 3^2)

So the fraction reduces to:

3^325
--------------------- =
3^325(3 + 9)

1
----
12

So, one twelfth it is.

Answer 7

= (3^325) / [(3^326).(3 + 1) ]
= [3^(325) / 3^(326) ] x (1 / 4)
= (1 / 3) x (1 / 4)
= 1 / 12
Note
3^(325) / 3^(326) = 1 / 3

Answer 8

(3^325)/(3^(326) + 3^(327))
(3^(325))/(3^(325 + 1) + 3^(325 + 2))
(3^(325))/(3(3^(325)) + (3^2)(3^(325)))
(3^(325))/((3^(325))(3 + 3^2))
1/(3 + 9)
1/12

Answer 9

grade 9 level hard math question

Answer 10

You can cancel out the exponents to reduce it to:

3^1 / (3^2 + 3^3)
3 / (9 + 27)
3 / 36
1/ 12

I don't believe your method is correct, but I'm not a math person...