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Identify the center and the radius of the circle with equation (x - 6)2 + y2 = 49.

center (0, -6) and radius = 7

center (0, 6) and radius = 49

center (-6, 0) and radius = 7

center (6, 0) and radius = 7

2007-06-18 09:45:48 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

consider the standard form of a circle about the origin:
x^2 + y^2 = r^2

to translate its center to the point (h,k), we write:
(x-h)^2 + (y-k)^2 = r^2

h=6, k=0 (since y-0=y), and r^2 = 49.

This means the radius is SQRT(49)=7 and the center is the point (6,0). That would be the fourth option.

2007-06-18 09:53:17 · answer #1 · answered by сhееsеr1 7 · 0 0

you're able to have revealed the equation as below. (x + 5)^2 + (y + 3)^2 = 40 9 ^2 potential squarred. The equation of a circle with centre (h, ok) and radius r is given with the aid of (x - h)^2 + (y - ok)^2 = r^2 comparing, centre is (-5, -3) and radius is 7.

2016-11-25 21:59:46 · answer #2 · answered by Anonymous · 0 0

(x - 6)² + (y - 0)² = 7²
Centre (6,0) and radius = 7

2007-06-18 20:32:06 · answer #3 · answered by Como 7 · 0 0

center (6,0) radius 7

2007-06-18 09:47:56 · answer #4 · answered by Anonymous · 0 0

I think that the center (6,0) and the radius is 7 but I dunno for sure.....I'm 95% sure.......or it's (0,-6) and the radius is 7. one of them is bound to be right.

2007-06-18 09:50:05 · answer #5 · answered by Anonymous · 0 2

OH! I just did that at school.
Um.. I guess it's (0,6) and radius 7.
Let me know if it's right.

2007-06-18 09:48:53 · answer #6 · answered by Sourkrout 3 · 0 0

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