Complete the ordered pairs so that each is a solution for the given equation?

Question

Complete the ordered pairs so that each is a solution for the given equation: 3x + 4y = 12 (0, ), ( , 3/4), ( , 0), (8/3, )?

Answer 1

Greetings,

Ok, this is really pretty easy, you are given an equation which of the form 3x + 4y = 12 , which has both x and y terms. Ordered pairs are of the form (x, y).

So in each of the ordered pairs, one value in pair is given, substitute that value in the equation and you'll be able to solve for the other value...

i.e (0,) the 'x' value is given... so
3(0) + 4y = 12
4y = 12
y = 3
the complete ordered pair is (0,3)

(,3/4), the 'y' value is given... so
3x + 4(3/4) = 12
3x + 3 = 12
3x = 9
x = 3
the complete ordered pair is (3,3/4)

(,0), y=0, so...

3x + 4(0) = 12
3x = 12
x = 4
(4,0)


(8/3, ), x = 8/3, so...
3(8/3) + 4y = 12
8 + 4y = 12
4y = 4
y = 1

(8/3, 1)

Hope this helps,

Cheers,
Mark

Answer 2

Ordered pairs like these come in the form of (x,y). So if x is given, then plug that into the equation and solve for y. Do vice versa if they give you y. So for example, with (0,?), this means x = 0 which gives us 3(0) + 4y = 12, so 4y=12 and y=3. This makes the ordered pair (0,3).

Answer 3

Substitute the number you know for the x or y in the equation and solve for the other one. For examp;e, with (8, ), you know the x value: 8 + 4y = -20 Subtract 8 from both sides: 4y = -28 Divide both sides by 4: y = -7 The point is (8, -7). Follow the same process, substituting -3 for y and 0 for x in the next questions.

Answer 4

y=3
x=3
x=4
y=1