English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Use this equation for the question.

-3x2 - 2x = -1

What is the value of a?
-3
3
-2

What is the value of b?
1
-2
2

What is the value of c?
1
-1
2


What are the solutions?
{-2/3, -1/10}
{1, 7}
{ -1, 1/3}

2007-06-18 08:24:19 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

Greetings,

First the general form of the quadratic equation

ax^2 +bx + c = 0

So you'll need to set up your expression -3x^2 -2x = -1 in a similar form, so your equation becomes, so for simplicity sake, lets move -3x^2, -2x to the right of the equal sign so that they have positive coefficients, you equation becomes

3x^2 + 2x -1 = 0

Now you can simply read off the coeffiecients

a = 3
b = 2
c = -1

You can factor the above equation into (3x - 1)(x + 1)
This gives you the solutions

3x -1 = 0 - OR - x + 1 = 0

x = 1/3, -1, the solutions


Hope this helps.

Cheers,
Mark

2007-06-18 08:37:30 · answer #1 · answered by Mark B 2 · 0 0

qudratic equation is
ax^2+bx+c=0
First set the equation equal to zero by adding one to both sides and you get
-3x^2-2x+1=0

therefore
a=-3
b=-2
c=1
the solution are
(-3x+1) (x+1)
x=1/3;-1
{1/3,-1}

2007-06-18 15:37:10 · answer #2 · answered by figgy16 1 · 0 0

fedest.com, questions and answers