Eg. like 8888,6543,9824,984,7653,6666,1234 etc.
2007-06-18 07:33:13 · 6 answers · asked by 10may 1 in Science & Mathematics ➔ Mathematics
9999-1000= 8999
2007-06-18 07:41:11 · answer #1 · answered by JAKE 3 · 0⤊ 0⤋
10^4 combinations
2007-06-18 07:36:17 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
if 0 can be a leading number then there are 10,000 combinations from 0000 to 9999.
if 0 can't be the first digit then there are 9999 combinations, from 1 - 9999
2007-06-18 07:37:46 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Oops at first I didn't include 1000 but I think this is right 9999-999= 9000
2007-06-18 07:38:43 · answer #4 · answered by ctmtz 2 · 0⤊ 0⤋
santmann2002 is correct if your going have 4 digit numbers
that have numbers that repeat such as 8888 7387 9529 .. etc
Kev is correct if you want all the possible 4 digit numbers
without having digits repeat.
10^4 (Permutation without replacement)
5040 (Permutation with replacement)
2007-06-18 07:45:44 · answer #5 · answered by ≈ nohglf 7 · 0⤊ 0⤋
10P4 = 10! / (10-4)!
= 10! / 6!
= 5040
2007-06-18 07:41:42 · answer #6 · answered by kev 2 · 0⤊ 0⤋