What is the equation for the line of symmetry for the graph of this function? y=(1)(x-3)2+(-1)?

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What is the equation for the line of symmetry for the graph of this function? y=(1)(x-3)2+(-1)?

2007-06-18 07:11:57 · 4 answers · asked by minnesotaskeptic 1 in Science & Mathematics ➔ Mathematics

4 answers

Hi,

The equation y=(1)(x-3)2+(-1) is in vertex form, y = a(x - h)² + k. That means the vertex is the point with coordinates (h,k), which in this case is (3,-1). since this equation is solved for y and the "a" value is positive, this graph opens upward. That means its axis of symmetry is the vertical line through the vertex. Therefore, x = 3 is the equation for the line of symmetry.

I hope this helps!! :-)

2007-06-18 07:14:41 · answer #1 · answered by Pi R Squared 7 · 0⤊ 0⤋

y=x-3

2007-06-18 14:16:47 · answer #2 · answered by Cool Nerd At Your Service 4 · 0⤊ 0⤋

x-3=0

2007-06-18 14:16:21 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋

x=3.5 or 7/2

2007-06-18 14:19:41 · answer #4 · answered by Anonymous · 0⤊ 0⤋