math problem?

Question

1. If the volume of a rectangular solid is 50 cubic feet. What is the volume of a rectangular solid that has twice the length, twice the width and twice the height of the first rectangular solid?
100 cubic feet
200 cubic feet
150 cubic feet
400 cubic feet

Answer 1

400ft^3

Imagine a rectangle of 1X1X1 - vol of 1ft^3
Then double the dimensions as in the problem above
2X2X2 = 8 ft^3

Doubling the length of all of the sides yields an 8X increase in the vol

Therefore 50X8 = 400

Answer 2

The easiest way for me to solve a question like this is to put it in terms of actual numbers. You know that given the way the question's asked, this would work for any rectangular solid that has a volume of 50 cubic feet--so come up with a rectangular solid with a volume of 50 cubic feet!

Length: 50 feet.
Width: 1 foot
Height: 1 foot.

50' * 1' * 1' = 50 cubic feet.

Now double it.

Length: 100 feet
Width: 2 feet
Height: 2 feet

100' * 2' * 2' = 400 cubic feet.

Answer 3

A1 = b x l x h = 50
2 x b x 2 x l x 2 x h = A2 = 8 x b x l x h
A2 = 8 x 50 = 400

Answer 4

400 cubic feet

Answer 5

400 cubic feet.
If you double one side, you will have double the cubic feet. You're doubling three sides, so you double it three times consecutively:

50(2)(2)(2)=400

Answer 6

400
V = base * width * hieght
pick random numbers that multioply to get 50
like 1*2*25 = 50 then double them
2*4*50 = 400cubic feet

Answer 7

d.
Volume = lwh. lwh = 50
2l 2w 2h = 50(8) = 400

Answer 8

400 cf

Answer 9

WHY DO YANKS SAY MATH??? ITS ACTUALLY MATHS [DOHH MATHEMATICS]