derivative of logx^2?

1 ⤊

2007-06-18 05:20:06 · 4 answers · asked by roadcrasher 1 in Science & Mathematics ➔ Mathematics

The derivative of log(x) is 1/x, so using the chain rule, the derivative of log(x^2) is 2x/x^2 = 2/x.

2007-06-18 05:25:06 · answer #1 · answered by TFV 5 · 1⤊ 0⤋

logx^2 = ln x^2 / ln 10

d (ln x^2) / dx = 2x / x^2 = 2 / x

the derivative is 2 / (x ln 10)

2007-06-18 05:54:04 · answer #2 · answered by bilbo 3 · 0⤊ 0⤋

let f(x) = log(x), then f'(x) = 1/x
let g(x) = x^2 , then f'(x) = 2x
by using the chain rule, if h(x) = log(x^2) , then h'(x) = [1/(x^2)](2x) = 2/x

2007-06-18 05:26:09 · answer #3 · answered by Amanda 2 · 0⤊ 0⤋

D(log(f(x)) = (f'(x)/f(x)) dx.

2007-06-18 05:24:29 · answer #4 · answered by Mathsorcerer 7 · 0⤊ 0⤋