Yes this type of question can get trippy. The trick is you know how many students there are:
Suppose the first five students are named Alice, Bob, Carol, Dave, and Elise. And the new student, lets call him Frank.
Then you have the averages:
(A+B+C+D+E)/5=15
(A+B+C+D+E+F)/6=14
You can rewrite the first equation as:
(A+B+C+D+E)/5*5=15*5=75
so
(A+B+C+D+E)=75
Then you can substitute that into the second equation
(A+B+C+D+E+F)/6=(75+F)/6=14
Solving for F we get F=14*6-75=9
So Frank, the new guy, is 9 years old!
2007-06-17 20:26:51
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answer #1
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answered by Hi 1
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The total age of the 5 students is 5 x 15 =75
The total age of the 6 students is 6 x 14 = 84
Therefore the last student is 84 - 75 = 9yrs old
2007-06-18 03:37:29
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answer #2
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answered by cosmic 2
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Yes this type of question can get tricky. The trick is to know how many students there are:
Suppose the first five students are named Alex, Beryl, Caarolinel, David, and Emma. And the new student, lets call him Fred
Then you have the averages:
(A+B+C+D+E)/5=15
(A+B+C+D+E+F)/6=14
You can rewrite the first equation as:
(A+B+C+D+E)/5*5=15*5=75
so
(A+B+C+D+E)=75
Then you can substitute that into the second equation
(A+B+C+D+E+F)/6=(75+F)/6=14
Solving for F we get F=14*6-75=9
So Frank, the new guy, is 9 years old!
2007-06-18 10:58:24
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answer #3
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answered by Anonymous
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Simple.
The 5 kids ages = 75 (5 x 15)
The 6 kids ages = 84 (6 x 14)
The sixths kids age is 9 (84 - 75)
Job done!
2007-06-18 10:45:08
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answer #4
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answered by brainyandy 6
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Let the first 5 students be a,b,c,d and e. So we have
(a+b+c+d+e)/5 = 15
Multiply both sides by 5 gives:
a+b+c+d+e = 75 ......Equation (1)
Now add the 6th student and you have:
(a+b+c+d+e+f)/6 = 14
Multiply both sides by 6 and you get:
a+b+c+d+e+f = 84 ..... Equation (2)
Take (1) from (2) and you get f = 9
So the age of the 6th student is 9 years.
2007-06-18 07:10:41
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answer #5
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answered by RATTY 7
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9 5 x 15 years average age mean that the total age of the 5 students is 75
If the average age of 6 stdents in 14 then their total age is 6x14 = 84
84 - 75 = 9 the new student is therefore 9 years old.
2007-06-18 03:28:52
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answer #6
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answered by Anonymous
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sum of the ages of first 5 students is 5 *15=75
sum of 6 students is 14* 6=84
age of the 6th student is 84-75=09
9 years is the age added of the student
2007-06-18 05:02:31
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answer #7
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answered by Anonymous
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we know that average of 5 people a,b,c,d,e is a+b+c+d+e divided by the number of addends
(a+b+c+d+e)/5=15
transpose 5 it became *
(a+b+C+d+e)=5*15
a+b+c+d+e=75
after adding f the average become 14
(a+b+c+d+e+f)/6=14
we then substitute a+b+c+d+e as 75
(75+f)/6=14
transpose /6 become *6
75+f=14*6
75+f=84
transpose +75 to become -75
f=84-75
f=9
then the answer is 9
2007-06-18 05:45:07
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answer #8
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answered by Elsie 1
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Total marks = 75
New total = 75 + x
New average = (75 + x) / 6
(75 + x) / 6 = 14
75 + x = 84
x = 9
Student was 9 years old.
2007-06-18 17:18:55
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answer #9
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answered by Como 7
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average age of one student =15yrs. total age of 5 students =5 x15
=75yrs.
1 student increased average age became =14 yrs.
thus total age of 6 students =6 x14
=84 yrs.
age of 6th student is= (age of 6) - (age of 5)
=84 - 75
=9yrs.
2007-06-19 08:32:56
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answer #10
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answered by billako 6
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