Find the volume of the solid formed by revolving the region bounded by the graphs y=x^3 , y=1, and x = 2 about the x axis.
2007-06-17 16:01:55 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
V = π∫x^6dx from x=0 to x = 1 plus π(1)(1^2) (from x = 1 to x = 2)
V = π(1 + (1/7)(1^7 - 0)
V = (8/7)π ≈ 3.590392 ≈ 3.59
2007-06-17 19:44:38 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
radius: 2+x^2 pi*INT[(2+x^2)^2dx] from 0 to a million word: you're able to upload 2 with the aid of fact the area the curve is removed from the rotating line is y+2. y=x^2. improve the binomial. (2+x^2)(2+x^2)=4+4x^2+x^4 pi*INT[4+4x^2+x^4 dx] from 0 to a million pi*[4x+(4/3)x^3+(a million/5)x^5] from 0 to a million. plu in a million pi[4+4/3 + a million/5] plu in 0 you get 0. pi[sixteen/3 + a million/5] pi[80 3/15] answer: 83pi/15.
2016-11-25 19:48:27 · answer #2 · answered by Anonymous · 0⤊ 0⤋