I need help to multiply and simplify this:
y^2 - 16 / 5y + 35 * y + 7 / y - 4
This is a headache, please solve this for me i would appreciate it.
2007-06-17 15:58:24 · 5 answers · asked by whatever 1 in Science & Mathematics ➔ Mathematics
No, i didn't, moron. Eff off if you're not helping kthx
2007-06-17 16:03:41 · update #1
Doug, they dont give it in parenthesis, and its the first one you listed
2007-06-17 16:07:47 · update #2
(y² - 16 / 5y) + (35 * y + 7 / y - 4)
2007-06-17 16:08:58 · update #3
if there is a variable (y) then you would need this equation to equal something, or zero. that is the only way you could figure this out. the order for any equation is division and multiplication first, then addition last.
2007-06-17 16:07:54 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Whoops...
(y² - 16 / 5y) + (35 * y + 7 / y - 4)
[(y-4) (y+4) / 5y] + [ 7(5y + 1) / y-4]
Take away the y-4's...
(y +4 / 5y) + [ 7(5y +1)]
Multiply each side by 5y...
(y +4) + [35y (5y + 1)]
(y+4) + 175 y^2 + 35y
175 y^2 + 36y + 4
Umm... I can't really get any farther... I'm sorry for the bad answer last time. I hope this one helps... Unless you already got it done...
2007-06-17 16:15:07 · answer #2 · answered by Daniel C 2 · 0⤊ 0⤋
The way you have it written, there are about a half-dozen different ways it could be interpreted. If you'd put parenthesis around terms, it sould make life so much easier. For example.... Is that first part
(y² - 16)/5y or is it
y² - (16/5y)
Doug
2007-06-17 16:05:39 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋
I agree with Doug. Even though you added some parenthesis, its still unclear what you mean.
Do you mean
[(y^2 - 16) / 5y + 35 ]* [(y + 7) / (y - 4)]?
Let me know before I try to help you
Ana
2007-06-18 02:26:51 · answer #4 · answered by MathTutor 6 · 0⤊ 0⤋
dude did you just make this up
2007-06-17 16:02:34 · answer #5 · answered by atif u 1 · 0⤊ 0⤋