What is 12 * (6 - 1) / 3 * 2² + 1?

Question

Thanks.

12 * (6 - 1) / 3 * 2² + 1

Answer 1

One step at a time.

12 * 5 / 3 * 2^2 +1
12 * 5 / 3 * 4 + 1
60 / 3 * 4 + 1
20 * 4 + 1
80 + 1
81

Answer 2

The order of operations is:
parentheses or grouping symbols,
exponents,
multiplication and division (from left to right)
addition and subtraction (left to right)

12*(6 - 1) / 3*2^2 + 1

= 12*5 / 3*2^2 + 1

= 12*5 / 3*4 + 1

= 60 / 3*4 + 1

= 20*4 + 1

= 80 + 1

= 81

Answer 3

12 * (6 - 1) / 3 * 2² + 1 =
12 * 5 / 3 * 2² + 1 =
12 * 5 / 3 * 4 + 1 =
60 / 3 * 4 + 1 =
20 * 4 + 1 =
80 + 1 =
81

Answer 4

= (12 x 5/3 x 4) + 1
= 80 + 1
= 81

Answer 5

First, follow BEDMAS***:

B rackets***
E xponents
D ivision
M ultiplication
A dding
S ubtrating

First solve all the problems in the brackets ((6-1)):

12 * [ (6 - 1) ] / 3 * 2² + 1 = 12 * 55 / 3 * 2² + 1

Then do the exponents (2²):

12 * 5 / 3 * [ 2² ] + 1 = 12 * 5 / 3 * 4 + 1

Then multiply and divide (12 * 5 ), ((12 * 5 ) / 3), and (((12 * 5 ) / 3 ) * 4):

[ [ [ 12 * 5 ] / 3 ] * 4 ] + 1 = [ [60 / 3 ] * 4 ] + 1 = [20 * 4] + 1 = 80 + 1

Add and Subtract (96+1):

[80 + 1] = 81

Solution:

81

*** Instead of BEDMAS, it can be PEDMAS (Parentheses replacing brackets)

Answer 6

81

12 * (6-1) / 3 * 2^2 +1 =
12 *5 /3 *4 +1 =
60/3 *4 +1 =
20*4 +1 =
81

Answer 7

PEMDAS

12 * (5) / 3 * 2^2 + 1
12 * 5 / 3 * 4 + 1
60 / 3 * 4 + 1
20 * 4 + 1
80 + 1
81

Answer 8

12 * (6 - 1) / 3 * 2² + 1

since parenthesis have the highest precedence:

12 * 5/3 * 4 + 1

and then next in precedence comes * and /:

60/12 + 1
5 + 1
6

no that's wrong, * and / have equal precedence so the 81 is correct.

Answer 9

(36÷4) + 5 - ( one million + {[( 2 × 3 ) + 12] ÷ 3} + one million) _ 9 _ + _ 5_ - { one million + [(6+12) div with the aid of three] +one million} _ _ _14_ _ _ - ( one million + _ _18/3_ _ + _ _ 1_ _ ) _ _ _ 14 _ _ _ - ( one million + _ _ 6 _ _ + _ _ one million _ _ ) _ _ _ 14 _ _ _ - ( _ _ _ _ _ 8 _ _ _ _ _ ) = 6

Answer 10

81 also