how do I divide this fraction?
2007-06-17 12:09:45 · 5 answers · asked by Jerry S 1 in Science & Mathematics ➔ Mathematics
x^2-49y^2 x^2+7xy
------------- /-------------- =
8x-56y
x^2-49y^2____1
------------- /-------------- =
8x-56y x^2+7xy
(x-7)(x+7)____1
------------- /-------------- =
8(x-7y)____x(x+7y)
1
----
8x
2007-06-17 12:17:45 · answer #1 · answered by Rachel Marie ♥ 4 · 0⤊ 2⤋
x^2-49y^2= (x+7y)(x-7y)
8x^2-56y=8(x-7y)
x^2+7xy=x(x+7y)
so
((x^2-49y^2) / (8x^2-56y)) / (x^2+7xy)=
(x+7y)(x-7y) 1
------------------------ =
8(x-7y) x(x+7y)
So cancel out the (x+7y) and (x-7y) from top and bottom
So you are left with
1/8x
2007-06-17 19:47:51 · answer #2 · answered by scotts1870 3 · 0⤊ 0⤋
x^2-49y^2/8x^2-56y divided by x^2+7xy
= [(x-7y)(x+7y)]/[8(x^2-7y)(x)(x+7y)]
= (x-7y)/[8x(x^2-7y)]
2007-06-17 19:34:32 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
(X-7Y)(X+7Y)/8(X^2-7Y)TIMES
1/X(X+7Y)
=X-7Y/8X(X^2-7Y)
2007-06-17 19:18:14 · answer #4 · answered by UNIQUE 3 · 0⤊ 0⤋
i dunno! sry. I'm just bored. ignore this answer!
2007-06-17 19:22:00 · answer #5 · answered by Anonymous · 0⤊ 1⤋