How to divide these cartesian complex numbers?

Question

Can anyone help me get the answer of dividing these two cartiesian complex numbers:

3+j7 / 6-j2

So basically i multiply the top by the opposite of the bottom? so 3+j7 / 6-j2 becomes 3+j7(6+j2) but where do i go from here i dont understand the next part of the solution?

ok so now i have:

(18+3j2+6j7-14) / 36

What happens next?

Answer 1

Multiply the numerator and denominator by the conjugate of
the denominator.

In this case the conjugate of the denominator is
(6 + j2)

Multiply and distribute through.
You should have a complex number in the numerator
and a real number in the denominator.

From there you can simplify the fraction.

****Edit****

You have to multiply Both the top and the bottom by
the conjugate which in this case is (6+j2).

so you would have

((3 + 7j) * (6+2j)) / ((6-2j) * (6+2j))



*Note: The imaginary number in the denominator should
disappear since you will have a number * j^2, where
j^2 = -1.

**Edit***

You forgot to add 4 to the denominator the denominator should be 40 since.
(6-2j) * (6+2j) = 36 + 12j - 12j -4j^2
= 36 - 4j^2
Remember that j^2 = -1
so that (6-2j) * (6+2j) = 40

*** In the numerator add/combine the "like terms" (add the real numbers to real numbers and the immaginary numbers with the immaginary numbers(numbers with the j component).

****Solution below**********
The answer should come out to be (48i+4)/40. Which
simplified is (12i+1)/(10)