could you please include the formula used to answer this.
2007-06-17 05:27:25 · 16 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
This does not mean words. It just wants to know how many combinations of the single letters you can have. ie: a,b,c,etc., ab, ac, ad, etc., abc, abd, abe, etc., abcd, abcf, etc.
2007-06-17 07:32:03 · update #1
26*25*24*23....*2*1
same as 26!
2007-06-17 05:33:40 · answer #1 · answered by Anonymous · 1⤊ 2⤋
Alphabet Combinations
2016-12-12 04:30:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Hi John B. In spite of the wording of the question, I suspect the student has misinterpreted the question. What is probably required is the permutations of the 26 letters of the alphabet, which I am sure you are aware is 26P26. I seriously doubt that the question requires the sum of all the possible lengths from 1 to 26.
2007-06-17 08:10:28 · answer #3 · answered by Anonymous · 0⤊ 0⤋
First Assumption - no repitition is allowed.
Second Assumption - any length, from 1 to 26 letters
Notation P(n,q) is the number of permutations of q elements from a set of size n.
P(26,1) = 26
P(26,2) = 26*25
P(26,3) = 26*25*24
The total (using the above assumptions) becomes the sumnation of all P(26,q) as q goes from 1 to 26.
That is P(26,1) + P(26,2) + P(26,3) + .... + P(26,25) + P(26,26)
Otherwise, as other have noted, it is an infinite amount because you can just keep adding letters at the end to cause a new combination
2007-06-17 07:13:41 · answer #4 · answered by John B 4 · 1⤊ 0⤋
You do not clarify your question.
Those 26 letters are used once in a word or combination or as many times you want?
If it is once, then the second answer to your question should do it for you.
2007-06-17 05:42:28 · answer #5 · answered by Airpole. 7 · 0⤊ 0⤋
In order to answer the question you need to know combinations of how many. The general formula is
C(26,n) = 26!/((n!)(26-n)!)
where n is the number of lettersin each combination.
2007-06-17 05:33:01 · answer #6 · answered by Anonymous · 1⤊ 0⤋
It depends how do you want to combine them...2 by 2, 3 by 3, 26 by 26.
If you combine 26 letter by 26 you have only one version.
If you want to arrange them (a, b, c....to a, c, b.....)
the formula is 26!/(26-26)!= 26!/0!= 26!/1= 26!=
403291461 × 10^18
2007-06-17 05:32:39 · answer #7 · answered by psycho_x52 2 · 0⤊ 2⤋
It depends on the length of the word. Since, technically, you can have a 'word' that is infinitely long, the possibilities are infinite as well.
If you limit yourself to a certain letter length, however, then it is a different story.
2007-06-17 05:35:42 · answer #8 · answered by The Red King 2 · 2⤊ 0⤋
Since there is no real limit to the length of the words that can be formed, and letters are repeated in words, a nearly infinite number. ~
2007-06-17 05:51:29 · answer #9 · answered by Anonymous · 1⤊ 1⤋
in each cobination a letter is there or not there so 2 choices for each letter, so number of combinations = 2^26
2007-06-17 05:30:23 · answer #10 · answered by Mein Hoon Na 7 · 0⤊ 3⤋