sin y = cos 2x calculouse help!!!!!!!!!!!!!!!?

Question

i have a math final that i'm studying for, and i cant seem to figure out how to do this.

i know i have to use implicit diffrenciation to figure this out, but i'm not so good at it, and i don't know what to do. please someone help me with a step by step process of what u did.


(use "d/d" for "dy/dx")

Answer 1

cosy *dy/dx= -sin2x *2 (using chain rule)
so dy/dx= -2sin2x /cosy
dy/dx =-2sin2x/cosy