help please with The Quadratic Formula?!?

Question

Solve for x using the quadratic formula. Remember that each equation must be in standard form before you take a, b, and c.
Can anyone help me solve these? But you don't have to if you don't want the points.

1: -10x2 + 11x + 24 = 20

2: -5x2 - 8x + 1 = 0

3. 6x2 - x - 5 = 0

4. -15x2 - 10x + 40 = 0

5. 3x2 + 4 = -7x

Answer 1

1. x= -.288 x=1.388 in which a=-10 b=11 c= 4
2. x= -1.717 x= .117 in which a=-5 b=-8 c=1
3. x= 1 x= -5/6 in which a=6 b--1 c=-5
4. x= -2 x= 4/3 in which a=-15 b=-10 c=40
5. x= -1 x= -4/3 in which a=3 b=7 c=4

plug into the quadratic formula

Answer 2

the quadratic formula is used to solve the possible variable solutions in quadratic equations, which are equations in which the a variable is squared. the formula itself is: x = -b (+/-) (square root of (b^2-4ac) / 2a so given 2x^2 +9x + 4 a= 2 b= 9 c= 4 so then plugging it into the equation: x= (-9) (+/-) square root (9^2-4(2) (4) / 2(2) simplified: x= -9 (+/-) square root (49) / 4 x= (-9 + 7)/ 4 or (-9 - 7) /4 solved: x = -1/2, or -4 hope that helps! good luck...

Answer 3

1)-10x^2+11x+4=0
2,3,and 4 are in standard form
5)3x^2+7x+4=0
I´ll show the solution of the last
x=((-7+-sqrt(49-4*3*4))/6 =(-7+-1)/6
x=-1 and x=-4/3

Answer 4

to get in to standerd for you must set each equal to zero.
the quadratic formula is neg b plus and minus the square root of b squared minus 4 times a times c all of that divided 2 times a
b=what ever is beside the x
a=whatever is beside thex2
c=whatever has no x
p.s. sorry its hard to show formulas on computer.